TAKS Item 8 Leads TEA to Flawed Reasoning
The Texas Education Agency (TEA), on August 6, 2003, issued a press release
regarding a problem in the Math section of the TAKS exam, a state exam for 10th
graders in Texas. The press release was disturbing for reasons the TEA
apparently did not consider. In fairness to the panel that reviewed this
question, it is possible that there was deep and meaningful discussion of the
true nature of the error that was committed, as well as the consequences of making various decisions. If so, the press release revealed none
of it.
The article states, “It was discovered … that item eight … could have been read
in such a way that the question had more than one correct answer.” The Houston
Chronicle (August 7), in turn, removed the qualifying phrase and simply reported that the problem “had more than one
correct answer.” Here is the question:
This is a straightforward question that cannot be interpreted in more than one
way; neither is it possible for an octagon to have more than one perimeter.
We can definitely rule out any possibility that there is more than one correct
answer.
However, it appears that we are not to worry about that. What is
important, it turns out, is how students approach the problem, rather than what
is correct. According to the Houston Chronicle, “the test-makers thought
students would use the Pythagorean Theorem to find the answer, which the agency
originally said was 36 centimeters…. After reviewing the question, the agency
realized that had a student used trigonometry, the answer could be 27
centimeters, which was another choice.” So, the TEA decided the fair thing
to do was give full credit for any answer.
Now excuse me, but, while different methods can result in slightly different
answers due to rounding, this is a glaring inconsistency. Math educators rightly
place a lot of emphasis on developing “number sense,” and the math educators in
charge of writing a statewide exam should have enough “number sense” of their
own to realize that there is something very wrong here. These "perimeters" show
a 25% deviation (or 33% depending on which you use as a base). Different methods
and rounding errors don’t produce variations like that.
What is really disturbing here is not that there was an error on the test, nor
that a faulty question was eliminated. Mistakes happen. The TEA says there have been only two errors in 23 years on the TAKS; if true, that is an exemplary record. What
is disturbing is the educators’
apparent indifference to the mathematical issue, i.e., What Really Went Wrong
Here? A cavalier acceptance of two widely divergent answers on a simple
perimeter problem, justified by the fact that two "correct" approaches to the
problem produced these answers, just illustrates the kind of “math illiteracy”
that so many educators complain about. Do we really want our future engineers
and architects to believe that the perimeter of some octagon could be either 27
or 36, and it doesn’t matter which you use, since both
are derived through "correct" methods? And, taking this to its
logical conclusion, we’ll just accept 41 or 18 as well! It really doesn’t matter;
after all, if "correct" methods give different answers, you may as well just guess! Take
any answer you like!
Another concern is the expectation that students
will use specific methods to solve the problem. In
fact, because this is a multiple choice problem, it is not necessary to
calculate a precise answer. It turns out that a simple estimation procedure that
requires neither the Pythagorean Theorem nor trigonometry could have been used.
An elementary student could do it. The perimeter of an octagon can be
approximated by the circumference of a circle. An inscribed circle with radius 4
will slightly underestimate the perimeter. Taking a diameter of 8, times 3 for pi
(rounding down just makes the estimate lower), gives 24. Thus the perimeter must
be a little more than 24. The only reasonable answer on the list is 27. Done in
five seconds, no calculator required. Still not sure? Let’s try a circumscribed
circle, using a radius of 4.6. This will overestimate the answer, so let’s just
round up to 5. Then the diameter is 10, which, multiplied by pi, gives
approximately 31.4. There can be no doubt that the perimeter must be between 24
and 31.4, so the only possible answer is 27.* (This agrees with the
trigonometric approach cited.)
But wait, using the Pythagorean Theorem gives approximately 36! How can this be?
We just found that the answer has to be less than 31.4! To diagnose the
problem requires a little trigonometry and a closer look at the diagram given.
If a right triangle has a leg of 4 and a hypotenuse of 4.6, the other leg is
approximately 2.27, which, multiplied by 16, gives the answer of 36. But what is
the angle between the first leg and the hypotenuse? Using the cosine inverse
function, we get approximately 29.6 degrees. If this were a regular octagon, the
angle would be exactly 22.5 degrees. (These dimensions would be about right for
a hexagon, which requires the angle to be 30 degrees.) So, the angle is over 30% too large, which
accounts for the fact that the perimeter is inflated by over 30%. If the
leg was intended to be 4, the hypotenuse could have been given as 4.33 instead
of 4.6 (yielding answers between 26.509 and 26.528 using different methods--now
that's the sort of variation you expect). Interestingly, the press release never
suggested that there might be something wrong with the drawing.
Since the given figure is geometrically impossible, there is really no solution
to the problem. Unfortunately, "None of the above" was not a choice. Given
the answers available, the only thing a reasonable person could do is mark 27.
But wait, the TEA spokesperson says, “It was just a coincidence that 27 was an
answer on the test. We always would attempt to just have one answer.” Hmmm. Math
illiteracy carries the day.
Dr. Dwight Galster
Asst. Professor of Statistics
South Dakota State University
References:
The Press Release
The Test
The Houston Chronicle "TAKS plays Solomon,
rules all answers right," August 7, 2003
*Alternatively, the perimeter can be estimated by using a square. The perimeter of the octagon must be less than that of the square pictured here, which is (apparently) 32.

On the other hand, the perimeter must be greater than that of the square shown here. This time we won't escape using the Pythagorean Theorem, which gives a side of approximately 6.5, and a perimeter of about 26.

So, we have a "proof" that, if this octagon exists, its perimeter must be between 26 and 32.
Another approach using circles, rather than employing a "squeeze theorem," would be to suggest that the perimeter must be close to that of a circle with radius about half-way between 4 and 4.6. The circumference of a circle with radius 4.3 is about 27.018!
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I retract much of what I said above--because Mark Loewe is right. I made the crucial error of assuming a point that appeared to be in the center was in fact the center, when it is not labeled as such.